1890 Belgian general election

1890 Belgian general election

10 June 1890 (1890-06-10)
69 of the 138 seats in the Chamber of Representatives 70 seats needed for a majority
First party Second party   150x150px Leader Auguste Beernaert Party Catholic Liberal Leader's seat Candidate for PM Seats before 98 seats 40 seats Seats won 29 40 Seats after 94 44 Seat change 4 4 Popular vote 17,253 20,829 Percentage 45.15% 54.51%
Government before election Beernaert Catholic Government after election Beernaert Catholic

Partial general elections were held in Belgium on 10 June 1890. In the elections for the Chamber of Representatives the result was a victory for the Catholic Party, which won 94 of the 138 seats.

Under the alternating system, elections were held in only four out of the nine provinces: Hainaut, Limburg, Liège and East Flanders. Thus, only 69 seats out of the 138 were up for election. Additionally, a special election was held in Neufchâteau on 3 June 1890.

Constituencies

The distribution of seats among the electoral districts was as follows:

Province	Arrondissement	Seats
Antwerp	Antwerp	8
	Mechelen	3
	Turnhout	3
Limburg	Hasselt	2
	Maaseik	1
	Tongeren	2
East Flanders	Aalst	4
	Oudenaarde	3
	Gent	8
	Eeklo	1
	Dendermonde	3
	Sint-Niklaas	3
West Flanders	Bruges	3
	Roeselare	2
	Tielt	2
	Kortrijk	4
	Ypres	3
	Veurne	1
	Diksmuide	1
	Ostend	1
Brabant	Leuven	5
	Brussels	16
	Nivelles	4
Hainaut	Tournai	4
	Ath	2
	Charleroi	7
	Thuin	3
	Mons	6
	Soignies	3
Liège	Huy	2
	Waremme	2
	Liège	9
	Verviers	4
Luxembourg	Arlon	1
	Marche	1
	Bastogne	1
	Neufchâteau	1
	Virton	1
Namur	Namur	4
	Dinant	2
	Philippeville	2